SOLUTION: In desperate need of your help! Given a table with statistics of crime- Residential: Robbery 130, Murder 40, Assault 30 Commercial: Robbery 102, Murder 28, Assault 20

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Question 1129998: In desperate need of your help!
Given a table with statistics of crime-
Residential: Robbery 130, Murder 40, Assault 30
Commercial: Robbery 102, Murder 28, Assault 20
*Find probability that crime committed in residential are is robbery.*
For this I found a solution of 13/20, however, I am not confident in the answer.
The second part
*find probability that crime was committed in a residential area given that it was an assault.
This one really has me scratching my head. Any advice, especially an explanation on how to solve such questions would be greatly appreciated.

Found 2 solutions by jim_thompson5910, MathLover1:
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

For part A, only focus on the "residential" row. We have 130 robberies, 40 murders, and 30 assaults. This totals to 130+40+30 = 200 residential crimes overall.

Of these 200 residential crimes, 130 are robberies.
So this leads to 130/200 = 13/20
Therefore, you have the correct answer. Nice work.

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In part B, we will only focus on the "assault" column because of the phrasing "given that it was an assault". There are 30 residential assaults and 20 commercial assaults leading to 30+20 = 50 total. Divide the residential assault count over the total assault count: 30/50 = 3/5

So the answer to part B is the fraction 3/5

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

you are right, it is 13%2F20;

all crimes in residential: 130%2B40%2B30=200
P(Robbery | in Residential area)
P%28130%2F200%29=+13%2F20