Question 1129926: Standard Normal Distribution: Assume the measurements given have a mean of 0 and a standard deviation of 1. Find the probability of the reading.
a. Less than 2.02
b. Greater than 1.45
c. Between 1.8 and 2.1
d. Greater than 2.08
*please explain how you got these b/c I am stuck
Standard Normal Distribution: Find the area, if there is a mean of 40 and a standard deviation of 5, for the following scenarios.
a. Greater than 32
b. Less than 55
c. Between 30 and 55
*please explain how you got these b/c I am stuck
Answer by Boreal(15235)   (Show Source):
You can put this solution on YOUR website! less than 2.02
on calculator, 2nd VARS 2 and (-6, 2.02) (you can use any other number less than -6 and get the same result. Some use -1E99
0.9783
Greater than 1.45 (1.45, 6)
0.0735
These, one wants the z-value
z=(x-mean)/sd
>(32-40)/5 or -8/5 or -1.6
z> -1.6 is probability (area) of
0.9452
Fewer than 55 is z <(55-40)/5 or z<3
This has probability of 0.9987
Between 30 and 55 is a z of (30-40)/5 or -2 and a z of 3
Probability is 0.9759
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