SOLUTION: 0° &#8804; &#952; < 360° 2sin(&#952;)-sqrt3=0 solve for &#952;

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Question 1129874: 0° ≤ θ < 360°
2sin(θ)-sqrt3=0
solve for θ
Found 2 solutions by MathLover1, ikleyn:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

2sin%28theta%29-sqrt%283%29=0+
2sin%28theta%29=sqrt%283%29+
sin%28theta%29=sqrt%283%29%2F2+
theta=sin%5E-1%28sqrt%283%29%2F2+%29
theta=pi%2F3...........(result in radians)
theta=60°


Answer by ikleyn(52803) About Me  (Show Source):
You can put this solution on YOUR website!
.
The correct answer is THIS : 

    The given equation has TWO solutions  60° and 120° in the given range.