SOLUTION: Theresa Morgan, a chemist, has a 25% hydrochloric acid solution and a 55% hydrochloric acid solution. How many liters of each should she mix to get 465 liters of a hydrochloric aci

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Question 1129873: Theresa Morgan, a chemist, has a 25% hydrochloric acid solution and a 55% hydrochloric acid solution. How many liters of each should she mix to get 465 liters of a hydrochloric acid solution with a 45% acid concentration?
___ liters of 25% of Hydroloric acid
___ Liters of 55% of Hydroloric acid

Found 2 solutions by josgarithmetic, josmiceli:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The question looks familiar and was maybe done already not more than a week ago.


x, amount of the 55% HCl
465-x, liters amount of the 25% HCl
55x%2B25%28465-x%29=45%2A465
-
55x-25x%2B25%2A465=45%2A465
30x=45%2A465-25%2A465
30x=20%2A465
x=%282%2F3%29465
x=310

310 liters of the 55% HCl
and
155 liters of the 25% HCl

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +a+ = liters of 25% solution needed
Let +b+ = liters of 55% solution needed
------------------------------------------------
(1) +a+%2B+b+=+465+
(2) +%28+.25a+%2B+.55b+%29+%2F+465++=+.45+
------------------------------------------------
(2) +.25a+%2B+.55b+=+209.25+
(2) +25a+%2B+55b+=+20925+
(2) +5a+%2B+11b+=+4185+
Multiply both sides of (1) by +5+ and subtract (1) from (2)
(1) +-5a+-+5b+=+-2325+
---------------------------------
+6b+=+1860+
+b+=+310+
and
(1) +a+%2B+310+=+465+
(1) +a+=+155+
----------------------------
155 liters of 25% mixture
310 liters of 55% mixture
-----------------------------
check:
(2) +%28+.25a+%2B+.55b+%29+%2F+465++=+.45+
(2) +%28+.25%2A155+%2B+.55%2A310+%29+%2F+465++=+.45+
(2) +%28+38.75+%2B+170.5+%29%2F465+=+.45+
(2) +%28+209.25+%29+%2F+465+=+.45+
(2) +209.25+=+.45%2A465+
(2) +209.25+=+209.25+
OKJ