SOLUTION: find all solutions to cosx=sinx+1 in the interval [0,2pi)

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Question 1129832: find all solutions to cosx=sinx+1 in the interval [0,2pi)
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
For both the sin and cos, the range is -1 to +1
So, the range of x is +pi+ to +2pi+
( the right side cannot be greater than 1 )
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+x+=+pi+
+cos%28+pi+%29+=+sin%28+pi+%29+%2B+1+
+-1+=+0+%2B+1+ not true
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+x+=+3%2A%28pi%2F2%29+
+cos%28+3%2A%28pi%2F2%29+%29+=+sin%28+3%2A%28pi%2F2%29+%29+%2B+1+
+0+=+-1+%2B+1+ true
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+x+=+2pi+
+cos%28+2pi+%29+=+sin%28+2pi+%29+%2B+1+
+1+=+0+%2B+1+ true
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+x+=+3%2A%28pi%2F2%29+ and
+x+=+2pi+
are the solutions