SOLUTION: the product of two consecutive integers is 7 less than three times their sum. Find the intergers

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Question 1129771: the product of two consecutive integers is 7 less than three times their sum. Find the intergers
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
let the consecutive integers be:
+n+ and +n%2B+1+
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+n%2A%28+n+%2B+1+%29+=+3%2A%28+n+%2B+n+%2B+1+%29+-+7+
+n%5E2+%2B+n+=+6n+%2B+3+-+7+
+n%5E2+-+5n+%2B+4+=+0+
+%28+n+-+4+%29%2A%28+n+-+1+%29+=+0+
+n+=+4+
+n+=+1+
------------------
+n+-+4+
+n+%2B+1+=+5+
+n%2A%28+n%2B+1+%29+=+3%2A%28+n+%2B+n+%2B+1+%29+-+7+
+4%2A5+=+3%2A%28+4+%2B+5+%29+-+7+
+20+=+27+-+7+
+20+=+20+
OK
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+n+=+1+
+n+%2B+1+=+2+
+n%2A%28+n%2B1+%29+=+3%2A%28+n+%2B+n+%2B+1+%29+-+7+
+1%2A2+=+3%2A%28+1+%2B+2+%29+-+7+
+2+=+9+-+7+
+2+=+2+
OK
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