SOLUTION: Complete sequence 14;8;6;4;5;=

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Question 1129691: Complete sequence 14;8;6;4;5;=
Found 3 solutions by greenestamps, Edwin McCravy, ikleyn:
Answer by greenestamps(13209) About Me  (Show Source):
You can put this solution on YOUR website!


Without any context to indicate what kind of sequence this might be, any problem of this kind can't be solved mathematically.

ANY next number makes a valid sequence, so there can't be a single "right" answer.

Spend a minute or two if you want to try to find a pattern. But in the end it will be a waste of time, because any pattern you find might not be the "right" one, and your answer will be "wrong".

Answer by Edwin McCravy(20063) About Me  (Show Source):
You can put this solution on YOUR website!
While the other tutor is right that there are many, many different
solutions, here is the POLYNOMIAL solution for the Nth term aN:



If you substitute 1,2,3,4 and 5 in that equation you will get the
first five terms. 



Here are the first 12 terms using that general equation:

14,8,6,4,5,19,63,161,344,650,1124,1818,...

Edwin

Answer by ikleyn(52878) About Me  (Show Source):
You can put this solution on YOUR website!
.
There are two correct answers to this question:

    1.  Any numbers can be next.

and


    2.  The problem, as it is formulated, has no Math sense.


Edwin presented some polynomial - but actually there are infinitely many polynomials with integer coefficients
producing the starting sequence and giving totally different next terms,
and there is NO WAY to choose "the right next term" between them.


So, the problems of this kind are pure speculations, that have no any relation/relations to Math.


I am wondering why professor Edwin McCravy supports such non-Math speculations in this forum.


Have a nice Thanksgiving day !