Question 1129554: There are 64 students in a class with the students offering at least one of the subjects literature, accounts and economics: 35 students offer literature, 32 offers accounts, and 40 offers economics. 17 offers both literature and accounts, 15 offer literature and economics, 12 offer economics and accounts. How many students offer two subjects only?
Answer by ikleyn(52835) (Show Source):
You can put this solution on YOUR website! .
You incorrectly use the words "offer" and "offering" in this post.
See how I edited it:
There are 64 students in a class with the students taking at least one of the subjects literature, accounting and economics:
35 students take literature, 32 take accounting, and 40 take economics. 17 take both literature and accounting,
15 take literature and economics, 12 take economics and accounting. How many students take two subjects only?
Solution
The idea of the solution is very simple:
To determine how much students study only literature and accounting, we take the number of 17 of those who study
literature and accounting and subtract from it the number of those who study all three subjects.
Similarly, to determine how much students study only literature and economics, we take the number of 15 of those
who study literature and economics and subtract from it the number of those who study all three subjects.
Finally, to determine how much students study only economics and accounting, we take the number of 12 of those
who study economics and accounting and subtract from it the number of those who study all three subjects.
So, we would get the answer momentarily, had we know the number of those who study all three subject.
Thus, it is the major unknown in this problem.
To find it, use this remarkable formula of the elementary set theory:
n(L U A U E) = n(L) + n(A) + n(E) - n(LnA) - n(LnE) - n(AnE) + n(LnAnE) (1)
which is valid for any three subsets L, A and E of the universal set U.
In formula (1), LnA is the intersection of the subsets L and A;
LnE is the intersection of the subsets L and E;
AnE is the intersection of the subsets A and E; and
LnAnE is the intersection of the THREE subsets L, A and E.
n(X) symbolizes the number of elements in subset X.
In our case L is the set of those who study literature; A is the set of those who study accounting;
LnA is the intersection of sets L and A, i.e. the set of those who study literature and accounting; and so on
(all designations are self-explanatory).
The last notice before applying the formula (1) is that the union L U A U E is the entire class consisting of 64 students,
so n(L U A U E) = 64.
Now substitute all other given input data into the formula (1). You will get
64 = 35 + 32 + 40 - 17 - 15 - 12 + n(LnAnE).
in the last formula, all the terms are known except the last one, so we easily get
n(LnAnE) = 64 - 35 - 32 - 40 + 17 + 15 + 12 = 1.
Now we are in position to answer each question:
- the number of those who study L and A is n(LnA) - n(LnAnE) = 17-1 = 16.
- the number of those who study L and E is n(LnE) - n(LnAnE) = 15-1 = 14.
- the number of those who study A and E is n(AnE) - n(LnAnE) = 12-1 = 11.
And, finally, the number of those who study exactly TWO subjects is 16 + 14 + 11 = 31. ANSWER
ANSWER. The number of those who study exactly TWO subjects is 31.
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If you want to have the proof of the formula (1), you may find it in my post
https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1129141.html
https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1129141.html
in this forum.
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If you want to see other similar solved problems and to see how the formula (1) works in other situations, look into the lessons
- Advanced problems on counting elements in sub-sets of a given finite set
- Challenging problems on counting elements in subsets of a given finite set
in this site.
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