SOLUTION: The length of a rectangle is 3 less than 5 times the width. the perimeter is 10 times the width find the demensions.

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Question 1129485: The length of a rectangle is 3 less than 5 times the width. the perimeter is 10 times the width find the demensions.
Found 4 solutions by josgarithmetic, MathTherapy, ikleyn, greenestamps:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
length, 5x-3
width , x
perimeter, 10x



%285x-3%29%2Bx=%2810x%29%2F2

Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!

The length of a rectangle is 3 less than 5 times the width. the perimeter is 10 times the width find the demensions.
As usual, IGNORE the RUBBISH posted by the other person.

Dimensions: 

cross%28%285x-3%29%2Bx=5%29 <===== This will NEVER get you a correct answer!!

Answer by ikleyn(52785) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let x be the width; then the length is (5x-3).


The equation is


    x + (5x-3) + x + (5x-3) = 10x


Simplify and solve for x:


    12x - 6 = 10x


    12x - 10x = 6


    2x = 6


    x = 6/2 = 3         - the width.     ANSWER


    5x-3 = 5*3-3 = 12   - the length.    ANSWER

Solved.


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


Let the width be w. Then the problem tells us the length is 3 less than 5 times the width:

l = 5w-3

We are also told that the perimeter (2l+2w) is 10 times the width:

2l+2w = 10w
2l = 8w
l = 4w

We have two different expressions for the length in terms of the width; those two expressions must be equal:

5w-3 = 4w
w = 3

l = 4w = 12

The rectangle is 12x3.