SOLUTION: Larry Mitchell invested part of his $38,000 advance at 6% annual simple interest and the rest at 2% annual simple interest. If this total yearly interest from both accounts was $88

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: Larry Mitchell invested part of his $38,000 advance at 6% annual simple interest and the rest at 2% annual simple interest. If this total yearly interest from both accounts was $88      Log On


   



Question 1129424: Larry Mitchell invested part of his $38,000 advance at 6% annual simple interest and the rest at 2% annual simple interest. If this total yearly interest from both accounts was $880 find the amount incested at each rate.
The amount invested at 6% is $ ?
The amount invested at 2% is $ ?

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let +x+ = amount invested @ 6%
+38000+-+x+ = amount invested @ 2%
-----------------------------------------------
+.06x+%2B+.02%2A%28+38000+-+x+%29+=+880+
+.06x+%2B+760+-+.02x+=+880+
+.04x+=+120+
+x+=+3000+
and
+38000+-+3000+=+35000+
@ 6%
$3,000
@2%
$35,000
---------------
check:
+.06%2A3000+%2B+.02%2A35000+=+880+
+180+%2B+700+=+880+
OK