SOLUTION: Can you please explain how to do the math for equations please i have a test tomorrow. mike had a jar of nickels that had 5 more nickels than he originally thought. if the total

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Question 1129402: Can you please explain how to do the math for
equations please i have a test tomorrow. mike had a jar of nickels that had 5 more nickels than he originally thought. if the total amount of nickels was 4.35, how many nickels did mike think he had originally?
Found 3 solutions by stanbon, math_helper, ankor@dixie-net.com:
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website!
mike had a jar of nickels that had 5 more nickels than he originally thought. if the total amount of nickels was 4.35, how many nickels did mike think he had originally?
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# he originally thought he had:: x
actual # of nickels:: x+5
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Note:: The 4.35 must refer to value of the nickels
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Equation:
5(x+5) = 435 cents
x+5 = 87
x = 82 (# of nickels he thought he had)
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Cheers,
Stan H.
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Answer by math_helper(2461)   (Show Source):
You can put this solution on YOUR website!
Let x be the number of nickels Mike thought he had.

We know the actual number is x+5, and, writing an equation for the value of those nickels:

5*(x+5) = 435 (in cents)
5x + 25 = 435 (distributed teh 5 into the paren's)
5x = 410 (subtracted 25 from each side)
x = 410/5 (divided each side by 5)
x = 82 (simplified)
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Answer: Mike originally thought he had nickels
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Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website!
mike had a jar of nickels that had 5 more nickels than he originally thought.
if the total amount of nickels was 4.35,
how many nickels did mike think he had originally?
let n = no. of nickels he thought he had
then
(n+5) = no. of nickels he actually had
.05(n+5) = 4.35
.05n + .25 = 4.35
.05n = 4.35 - .25
.05n = 4.10
n = 4.10/.05
n = 82 nickels he thought he had
;
:
Check this
Actual no. 82+5 = 87
.05*87 = 4.35