Question 1129355: how many pounds of a 16% aluminum alloy must be mixed with 300lb of a 37% aluminum alloy to make a 22% aluminum alloy? Found 2 solutions by addingup, ankor@dixie-net.com:Answer by addingup(3677) (Show Source):
You can put this solution on YOUR website! 16% = x
37% = 300 - x
0.16x + 0.37(300-x) = 0.22(300)
0.16x + 111 - 0.37x = 66
-0.21x = -45
x = 214.3 pounds of 16% have to be mixed with 300-214.3 = 85.7 pounds of 37% to make 300 pounds of 22% aluminum
You can put this solution on YOUR website! how many pounds of a 16% aluminum alloy must be mixed with 300lb of a 37% aluminum alloy to make a 22% aluminum alloy?
:
let x = 16% alloy
:
The mixture equation
.16x + .37(300) = .22(x+300)
.16x + 111 = .22x + 66
.16x - .22x = 66 - 111
-.06x = -45
x = -45/-.06
x = +750 lb of 16% alloy required
:
:
Check this yourself
.16(750) + .37(300) = .22(750+300)
