SOLUTION: hello all, I wrote on here a couple days ago asking for help with my algebra homework with the linear equations. I understand now to do ones with the variables on the t

Algebra ->  Linear-equations -> SOLUTION: hello all, I wrote on here a couple days ago asking for help with my algebra homework with the linear equations. I understand now to do ones with the variables on the t      Log On


   



Question 1129302: hello all,
I wrote on here a couple days ago asking for help with my algebra homework with the linear equations. I understand now to do ones with the variables on the two sides of the equality like y=3x-2. I know that X=0 and also 3 and Y=2 and 0 on the T chart for the graphing.
Now the part that I'm having a hard time with is when the X and Y are on the same side of the equality like for example 2x+3=6. I'm having a rough time getting the T chart X and Ys for these problems.
any help would be really helpful as I have a quiz on Tuesday that I don't wanna fail.
Two ther examples of the ones I don't understand are 2x-3y=6 and also 3x+4y=12
thank you so much in advance.

Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

the equality like y=3x-2 is linear equality in slope-intercept form y=mx%2Bb where m is a slope and b is y-intercept
so, in case above m=3 is a slope and b=-2 is y-intercept
if you want to graph that line, you need two points (line is defined by two points)
since you already have that y-intercept (means x=0 is -2, one point is
(0,-2)
for second point you can choose to find x-intercept, when y=0
y=3x-2=>2=3x=>x=2%2F3

(2%2F3,0)

now, plot the points and draw a line through




Two other examples:
2x-3y=6 and +3x%2B4y=12 are written in a standard form ax%2Bby=c
to graph them, you need two points
you can choose any value for x and calculate y, or you can
find x and y-intercepts,which is easier
you do same as above; set x=0 to find y-intercept,
2%2A0-3y=6 ->-3y=6 ->y=6%2F-3 ->y=-2

and set y=0 to find x-intercept
2x-3%2A0=6->2x=6->x=6%2F2->x=3
so, points are:
(0-2) -> y-intercept
(30) -> x-intercept

plot:



and +3x%2B4y=12
set y=0 to find x-intercept
3x%2B4%2A0=12->3x=12->x=4

set x=0 to find y-intercept
+3%2A0%2B4y=12->4y=12->y=3

so, points are:
(40) -> x-intercept
(03) -> y-intercept
plot:




Answer by MathTherapy(10552) About Me  (Show Source):
You can put this solution on YOUR website!
hello all,
I wrote on here a couple days ago asking for help with my algebra homework with the linear equations. I understand now to do ones with the variables on the two sides of the equality like y=3x-2. I know that X=0 and also 3 and Y=2 and 0 on the T chart for the graphing.
Now the part that I'm having a hard time with is when the X and Y are on the same side of the equality like for example 2x+3=6. I'm having a rough time getting the T chart X and Ys for these problems.
any help would be really helpful as I have a quiz on Tuesday that I don't wanna fail.
Two ther examples of the ones I don't understand are 2x-3y=6 and also 3x+4y=12
thank you so much in advance.
You asked for a T-chart and nothing else. I don't know why the other person did everything except give you a T-chart.
I think you meant, 2x + 3y = 6, and NOT 2x + 3 = 6
Now, we get: 3y = - 2x + 6, and we can clearly see that the right side needs to be DIVIDED by 3, so this is why I chose values that are MULTIPLES of 3, and including 0.
These are: 0, 3, 6, 9, and 12. With that, I'm able to get integer values for y.
You now have 5 points with which to plot the graph, since you need to set up a T-table.
===============
xyCoordinate Point
0 3y = - 2(0) + 6_____3y = 6_____y = 2 (0, 2)
3 3y = - 2(3) + 6_____3y = 0_____y = 0 (3, 0)
6 3y = - 2(6) + 6_____3y = - 6_____y = - 2 (6, - 2)
93y = - 2(9) + 6_____3y = - 12_____y = - 4 (9, - 4)
123y = - 2(12) + 6_____3y = - 18_____y = - 6 (12, - 6)

You should now be able to do the other 2 equations: 2x - 3y = 6 and 3x + 4y = 12, by using the same method. If not, write back!