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| Question 1129302:  hello all,
 I wrote on here a couple days ago asking for help with my algebra homework with the linear equations. I understand now to do ones with the variables on the two sides of the equality like y=3x-2. I know that X=0 and also 3 and Y=2 and 0 on the T chart for the graphing.
 Now the part that I'm having a hard time with is when the X and Y are on the same side of the equality like for example 2x+3=6. I'm having a rough time getting the T chart X and Ys for these problems.
 any help would be really helpful as I have a quiz on Tuesday that I don't wanna fail.
 Two ther examples of the ones I don't understand are 2x-3y=6 and also 3x+4y=12
 thank you so much in advance.
 Found 2 solutions by  MathLover1, MathTherapy:
 Answer by MathLover1(20850)
      (Show Source): 
You can put this solution on YOUR website! the equality like
  is linear equality in  -  form  where  is a slope and  is y-intercept so, in case above
  is a slope and  is y-intercept if you want to graph that line, you need two points (line is defined by two points)
 since you already have that y-intercept (means
  is  , one point is (
  ,  ) for second point you can choose to find x-intercept, when
   
  =>  =>   
 (
  ,  ) 
 now, plot the points and draw a line through
 
 
   
 
 Two other examples:
 
  and  are written in a standard form   to graph them, you need two points
 you can choose any value for
  and calculate  , or you can find
  and  -intercepts,which is easier you do same as above; set
  to find y-intercept, 
  ->  ->  ->   
 and set
  to find x-intercept 
  ->  ->  ->   so, points are:
 (
   ) -> y-intercept (
   ) -> x-intercept 
 plot:
 
   
 
 and
   set
  to find x-intercept 
  ->  ->   
 set
  to find y-intercept 
  ->  ->   
 so, points are:
 (
   ) -> x-intercept (
   ) -> y-intercept plot:
 
   
 
 
Answer by MathTherapy(10556)
      (Show Source): 
You can put this solution on YOUR website! hello all, I wrote on here a couple days ago asking for help with my algebra homework with the linear equations. I understand now to do ones with the variables on the two sides of the equality like y=3x-2. I know that X=0 and also 3 and Y=2 and 0 on the T chart for the graphing.
 Now the part that I'm having a hard time with is when the X and Y are on the same side of the equality like for example 2x+3=6. I'm having a rough time getting the T chart X and Ys for these problems.
 any help would be really helpful as I have a quiz on Tuesday that I don't wanna fail.
 Two ther examples of the ones I don't understand are 2x-3y=6 and also 3x+4y=12
 thank you so much in advance.
 
 You asked for a T-chart and nothing else. I don't know why the other person did everything except give you a T-chart.I think you meant, 2x + 3y = 6, and NOT 2x + 3 = 6
 Now, we get: 3y = - 2x + 6, and we can clearly see that the right side needs to be DIVIDED by 3, so this is why I chose values that are MULTIPLES of 3, and including 0.
 These are: 0, 3, 6, 9, and 12. With that, I'm able to get integer values for y.
 You now have 5 points with which to plot the graph, since you need to set up a T-table.
 ===============
 
 
| x | y | Coordinate Point | 
|---|
 | 0 | 3y = - 2(0) + 6_____3y = 6_____y = 2 | (0, 2) |  | 3 | 3y = - 2(3) + 6_____3y = 0_____y = 0 | (3, 0) |  | 6 | 3y = - 2(6) + 6_____3y = - 6_____y = - 2 | (6, - 2) |  | 9 | 3y = - 2(9) + 6_____3y = - 12_____y = - 4 | (9, - 4) |  | 12 | 3y = - 2(12) + 6_____3y = - 18_____y = - 6 | (12, - 6) |  You should now be able to do the other 2 equations: 2x - 3y = 6 and 3x + 4y = 12, by using the same method. If not, write back!
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