SOLUTION: Find 4 consecutive odd integers where the sum of the 2nd and the 4th is 70

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Question 1129194: Find 4 consecutive odd integers where the sum of the 2nd and the 4th is 70
Found 2 solutions by josgarithmetic, greenestamps:
Answer by josgarithmetic(39630) About Me  (Show Source):
You can put this solution on YOUR website!
system%28n%2C+n%2B2%2C+n%2B4%2C+n%2B6%29

n%2B2%2Bn%2B6=70
2n%2B8=70
n%2B4=35
n=31

31, 33, 35, 37

Answer by greenestamps(13209) About Me  (Show Source):
You can put this solution on YOUR website!


In a sequence of consecutive odd integers -- as in any arithmetic sequence -- the 3rd term is the average of the 2nd and 4th terms.

In this problem the sum of the 2nd and 4th is 70, so their average is 70/2=35.

Then since the 3rd of the 4 consecutive odd integers is 35, the sequence is 31, 33, 35, 37.