SOLUTION: three girls share a packet of sweet. the first received 2/5 of the sweets. the second received 5/9 of the remainder and the third got 8 sweets.how many sweet were in the packet?
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-> SOLUTION: three girls share a packet of sweet. the first received 2/5 of the sweets. the second received 5/9 of the remainder and the third got 8 sweets.how many sweet were in the packet?
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Question 1129133: three girls share a packet of sweet. the first received 2/5 of the sweets. the second received 5/9 of the remainder and the third got 8 sweets.how many sweet were in the packet? Found 2 solutions by ankor@dixie-net.com, MathTherapy:Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! three girls share a packet of sweet. the first received 2/5 of the sweets.
the second received 5/9 of the remainder and the third got 8 sweets.
how many sweet were in the packet?
:
let a = total amt of sweets
change 2/5 to .4, simplify dealing with fractions
a = .4a + (a-.4a) + 8
a = .4a + (.6a) + 8
multiply equation by 9 to get rid of the denominator
9a = 9(.4a) + 5(.6a) + 9(8)
9a = 3.6a + 3a + 72
9a = 6.6a + 72
9a - 6.6a = 72
2.4a = 72
a = 72/2.4
a = 30 sweets in the packet
:
:
See if that checks out * 30 = 12 for the 1st girl * 18 = 10 for the 2nd girl (subtracted 12 from the total)
3rd girl: 8
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total 30
You can put this solution on YOUR website!
three girls share a packet of sweet. the first received 2/5 of the sweets. the second received 5/9 of the remainder and the third got 8 sweets.how many sweet were in the packet?
With the 1st girl getting , remains
With the 2nd girl getting of remainder,
With the 3rd receiving , we get: , with N being the original number
4N = 8(15) ------ Cross-multiplying
N, or original number =
