SOLUTION: how do you express ln under root 13.5 in term of ln2 and ln3?

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Question 1129127: how do you express ln under root 13.5 in term of ln2 and ln3?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

ln+%28sqrt%28+13.5+%29%29............write 13.5 as 27%2F2=3%5E3%2F2

= ln+%28sqrt%28+3%5E3%2F2+%29%29

= ln+%283%2Fsqrt%28+2+%29%29

= ln+%283%29-ln%28sqrt%28+2+%29%29

= ln+%283%29-ln%28+2%5E%281%2F2+%29%29

= ln+%283%29-%281%2F2+%29ln%28+2%29