SOLUTION: Solve for x in the given interval. sec x=(2sqrt3)/3 ((3pi)/2)≤x ≤(2pi)

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Question 1129006: Solve for x in the given interval.
sec x=(2sqrt3)/3
((3pi)/2)≤x ≤(2pi)

Answer by Edwin McCravy(20060) About Me  (Show Source):
You can put this solution on YOUR website!

sec%28x%29=%282sqrt%283%29%29%2F3
First we take the reciprocals of both sides, using the
fact that the reciprocal of the secant is the cosine:
cos%28x%29=3%2F%282sqrt%283%29%29
Rationalize the denominator on the right side:

cos%28x%29=expr%28%283sqrt%283%29%29%2F%282sqrt%283%29%2Asqrt%283%29%29%29
cos%28x%29=%283sqrt%283%29%29%2F%282%2A3%29
cos%28x%29=%28sqrt%283%29%29%2F2
This is positive, and the cosine is positive in QI and QIV
From the unit circle, we get the first quadrant answer as 30°
or pi%2F6
The interval %283pi%29%2F2+%3C=x%3C=2pi is Q4,
So to get the angle in Q4, we subtract from 2pi.
2pi-pi%2F6=12pi%2F6-pi%2F6=11pi%2F6
Answer: 11pi%2F6
Edwin