SOLUTION: Newport and Vernonville are 208 miles apart. A car leaves Newport traveling towards​ Vernonville, and another car leaves Vernonville at the same​ time, traveling toward
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Question 1128853: Newport and Vernonville are 208 miles apart. A car leaves Newport traveling towards Vernonville, and another car leaves Vernonville at the same time, traveling towards Newport. The car leaving Newport averages 10 miles per hour more than the other, and they meet after 1 hour and 36 minutes. What are the average speeds of the cars? Found 2 solutions by ikleyn, josmiceli:Answer by ikleyn(52759) (Show Source):
Let x be the rate of the slower car, in miles per hour.
Then the rate of the faster car is (x+10) mph.
Then the total distance equation is
= 208 miles. <<<---=== is 1 hour and 36 minutes
To solve it, multiply by 60 both sides
96x + 96x + 960 = 208*60
192x = 208*60 - 960
192x = 11520 ====> x = = 60 miles per hour.
Answer. The slower car rate is 60 mph; the faster car rate is 70 mph.
You can put this solution on YOUR website! Add their speeds
Let = ave speed of the slower car = ave speed of the faster car
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and
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The speeds are 60 mi/hr and 70 mi/hr