SOLUTION: Newport and Vernonville are 208 miles apart. A car leaves Newport traveling towards​ Vernonville, and another car leaves Vernonville at the same​ time, traveling toward

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Question 1128853: Newport and Vernonville are 208 miles apart. A car leaves Newport traveling towards​ Vernonville, and another car leaves Vernonville at the same​ time, traveling towards Newport. The car leaving Newport averages 10 miles per hour more than the​ other, and they meet after 1 hour and 36 minutes. What are the average speeds of the​ cars?
Found 2 solutions by ikleyn, josmiceli:
Answer by ikleyn(52759) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let x be the rate of the slower car, in miles per hour.

Then the rate of the faster car is (x+10) mph.


Then the total distance equation is


    %2896%2F60%29%2Ax+%2B+%2896%2F60%29%2A%28x%2B10%29 = 208  miles.    <<<---===  96%2F60 is 1 hour and 36 minutes


To solve it, multiply by 60 both sides


    96x + 96x + 960 = 208*60

    192x = 208*60 - 960

    192x = 11520  ====>  x = 11520%2F192 = 60 miles per hour.


Answer.  The slower car rate is 60 mph;  the faster car rate is 70 mph.

Solved.



Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Add their speeds
Let +s+ = ave speed of the slower car
+s+%2B+10+ = ave speed of the faster car
--------------------------------------------
+208+=+%28+s+%2B+s+%2B+10+%29%2A%28+1+%2B+36%2F60+%29+
+208+=+%28+2s+%2B+10+%29%2A%28+96%2F60+%29+
+%28+60%2F96+%29%2A208+=+2s+%2B+10+
+130+=+2s+%2B+10+
+2s+=+120+
+s+=+60+
and
+s+%2B+10+=+70+
---------------------
The speeds are 60 mi/hr and 70 mi/hr