SOLUTION: If g(x) = 4lnx + 1, what is the value of g^-1(ln 81 + 1)

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Question 1128775: If g(x) = 4lnx + 1, what is the value of g^-1(ln 81 + 1)
Answer by Shin123(626) About Me  (Show Source):
You can put this solution on YOUR website!
g(x)=4lnx +1 g-1(ln 81+1)= ? If we let the unknown be y, we get this:
g%5E-1%28ln+81+%2B1%29=y Using the definition of an inverse, we can rearrange the equation to make it look like this:
g%28y%29=ln+81%2B1 4lny+1=ln 81+1
4lny=ln 81
4lny=4ln 3
lny=ln 3
highlight%28y=3%29