SOLUTION: Find the equation of the circle tangent to x+y=3 at (1,2) and through (3,6).

Algebra ->  Circles -> SOLUTION: Find the equation of the circle tangent to x+y=3 at (1,2) and through (3,6).      Log On


   

Question 1128675: Find the equation of the circle tangent to x+y=3 at (1,2) and through (3,6).
Answer by Alan3354(69443) About Me  (Show Source):
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Find the equation of the circle tangent to x+y=3 at P(1,2) and through Q(3,6).
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The center of the circle is on the line perpendicular to x+y=3 and thru the point P.
The center of the circle is on the perpendicular bisector of PQ, so the intersection of those 2 lines is the center.
The radius is the distance from the center to P or Q.