SOLUTION: What is the probability of (B|A) if P(A) =.50; P(B) =.80; P(AnB) =.20; P(B|A) =.40 P(AuB) =.90

Algebra ->  Probability-and-statistics -> SOLUTION: What is the probability of (B|A) if P(A) =.50; P(B) =.80; P(AnB) =.20; P(B|A) =.40 P(AuB) =.90      Log On


   

Question 1128569: What is the probability of (B|A) if P(A) =.50; P(B) =.80; P(AnB) =.20; P(B|A) =.40 P(AuB) =.90
Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The given probabilities are not possible.

P(AuB) = P(A)+P(B)-P(AnB)

With the given probabilities, that is .50+.80=.20 = 1.10. But a probability can't be greater than 1.

Re-post the problem with the right numbers.