SOLUTION: I need to rearrange the formula {{{ a^x = 5^(x-1) }}} to make x the subject. So far I have used the log rule to get xlog a = (x-1)log 5 , but I am unsure where to go from here. Th

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I need to rearrange the formula {{{ a^x = 5^(x-1) }}} to make x the subject. So far I have used the log rule to get xlog a = (x-1)log 5 , but I am unsure where to go from here. Th      Log On


   



Question 1128248: I need to rearrange the formula +a%5Ex+=+5%5E%28x-1%29+ to make x the subject. So far I have used the log rule to get xlog a = (x-1)log 5 , but I am unsure where to go from here.
Thank you.

Answer by josgarithmetic(39620) About Me  (Show Source):