SOLUTION: assume that a box contains three red jelly beans and two green ones. We consider the event that a red bean is drawn. Suppose I pick a jelly bean from the box without looking, and

Algebra ->  Probability-and-statistics -> SOLUTION: assume that a box contains three red jelly beans and two green ones. We consider the event that a red bean is drawn. Suppose I pick a jelly bean from the box without looking, and       Log On


   



Question 1128176: assume that a box contains three red jelly beans and two green ones. We consider the event that a red bean is drawn. Suppose I pick a jelly bean from the box without looking, and I do not put the bean back in the box. Then I choose again. What is the probability of getting two red beans
Found 2 solutions by Boreal, ikleyn:
Answer by Boreal(15235) About Me  (Show Source):
You can put this solution on YOUR website!
(3/5) probability first is red*(2/4) probability second is red. The second one changes both the numerator and the denominator.
That is 3/10 probability of getting two reds.

Answer by ikleyn(52847) About Me  (Show Source):
You can put this solution on YOUR website!
.

The probability under the question is

    %283%2F%283%2B2%29%29%2A%282%2F4%29 = %283%2F5%29%2A%282%2F4%29 = 6%2F20 = 3%2F10 = 0.3 = 30%.


This formula is self-explanatory.  If you have questions,  look into the formula attentively,  and then it will tell you everything about itself.

So,  my explanations are not required.


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This problem is the TWIN to the problem which I solved under the link

https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1128157.html

https://www.algebra.com/algebra/homework/Probability-and-statistics/Probability-and-statistics.faq.question.1128157.html


Compare them to better learn this subject.