SOLUTION: Find the equation of the line, in slope-intercept form, that satisfies the given conditions. The graph is perpendicular to the graph of y = 5x − 1 and passes through the

Algebra ->  Graphs -> SOLUTION: Find the equation of the line, in slope-intercept form, that satisfies the given conditions. The graph is perpendicular to the graph of y = 5x − 1 and passes through the      Log On


   



Question 1128008: Find the equation of the line, in slope-intercept form, that satisfies the given conditions.
The graph is perpendicular to the graph of
y = 5x − 1
and passes through the point whose coordinates are
(2, −2).

Found 2 solutions by MathLover1, josgarithmetic:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
the equation of the line, in slope-intercept form, that satisfies the given conditions.
The graph is perpendicular to the graph of
y+=+5x+-+1-> slope m=5
perpendicular lines have slopes negative reciprocal to each other, so
perpendicular line will have a slope -1%2F5
so far, equation is:
y=-%281%2F5%29x%2Bb
and if passes through the point whose coordinates are
(2, -2), we have
-2=-%281%2F5%292%2Bb
-2=-%282%2F5%29%2Bb
-2%2B%282%2F5%29=b
b=-10%2F5%2B2%2F5
b=-8%2F5
and, equation is: y=-%281%2F5%29x-8%2F5





Answer by josgarithmetic(39620) About Me  (Show Source):