SOLUTION: The time, T, in seconds, a pendulum takes to move back and forth once is 2Π times the square root of the length of the pendulum, L, in feet, divided by the square root of the

Algebra ->  Rational-functions -> SOLUTION: The time, T, in seconds, a pendulum takes to move back and forth once is 2Π times the square root of the length of the pendulum, L, in feet, divided by the square root of the       Log On


   

Question 1128004: The time, T, in seconds, a pendulum takes to move back and forth once is 2Π times the square root of the length of the pendulum, L, in feet, divided by the square root of the acceleration due to gravity, 32 feet/second2. Enter the correct values in the equation with respect to the motion of the pendulum.
2Π
T
32
L
1.82
7.29
0.55
Answer by ikleyn(52834) About Me  (Show Source):
You can put this solution on YOUR website!
.
I see two and only two possibilities: 

    1.  You EITHER know and understand the meaning of written words - and then you can follow them and do it on your own;


OR


    2.  You don't know and do not understand the meaning of written words - and then you are in wrong class.