SOLUTION: The length of a rectangle is 4 ft more than twice the width. The area of the rectangle is 160 ft2. Find the length and width of the rectangle

Algebra ->  Customizable Word Problem Solvers  -> Geometry -> SOLUTION: The length of a rectangle is 4 ft more than twice the width. The area of the rectangle is 160 ft2. Find the length and width of the rectangle      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1127950: The length of a rectangle is 4 ft more than twice the width. The area of the rectangle is 160 ft2. Find the length and width of the rectangle
Answer by math_helper(2461) About Me  (Show Source):
You can put this solution on YOUR website!
LW = 160 sqft
(2W+4)(W) = 160
+2W%5E2+%2B+4W+-+160+=+0+
+2%28W%5E2+%2B+2W+-+80%29+=+0+
+2%28W-8%29%28W%2B10%29+=+0+
W = 8 —> L = 2*8+4 = 20
—
Ans: Length is 20ft, width is 8ft
—
Chk: 8*20 = 160