Question 1127836:  Solve the of equation 2x-y+z=-7, x-3y+4z=-19, and -x+4y-3z=18.
 
A. There is one solution (-1,2,-3) 
B. There is one solution (1,-2,3) 
C. There is one solution (-1,-2,-3) 
D. There is one solution (1,2,3) 
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Solve the of equation 2x-y+z=-7, x-3y+4z=-19, and -x+4y-3z=18.
 
A. There is one solution (-1,2,-3) 
B. There is one solution (1,-2,3) 
C. There is one solution (-1,-2,-3) 
D. There is one solution (1,2,3) 
2x - y + z = - 7 -------- eq (i) 
x - 3y + 4z = - 19 ------ eq (ii) 
- x + 4y - 3z = 18 ------ eq (iii) 
        y + z = - 1 -------- Adding eqs (iii) & (ii) ------ eq (iv) 
- 2x + 8y - 6z = 36 -------- Multiplying eq (iii) by 2 ------ eq (v) 
       7y - 5z = 29 -------- Adding eqs (v) & (i) ------ eq (vi) 
       5y + 5z = - 5 ------- Multiplying eq (iv) by 5 ------ eq (vii) 
12y = 24 ------ Adding eqs (vii) & (vi) 
  
2 + z = - 1 ------ Substituting 2 for y in eq (iv) 
  
2x - 2 + - 3 = - 7 ------ Substituting 2 for y, and - 3 for z in eq (i) 
2x - 5 = - 7 
2x = - 7 + 5 
2x = - 2 
  
Now, you choose the correct answer!  
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