SOLUTION: Find the inverse of the function. (Enter the domain using interval notation.) f(x) = sqrt (4x − 6) + 3 * I know that the inverse of the function is f(x)= x^2-6x+15/ 4. Howe

Algebra ->  Functions -> SOLUTION: Find the inverse of the function. (Enter the domain using interval notation.) f(x) = sqrt (4x − 6) + 3 * I know that the inverse of the function is f(x)= x^2-6x+15/ 4. Howe      Log On


   



Question 1127791: Find the inverse of the function. (Enter the domain using interval notation.)
f(x) = sqrt (4x − 6) + 3
* I know that the inverse of the function is f(x)= x^2-6x+15/ 4. However, I am running into trouble finding the domain. My answers so far have been, (- infinity, + infinity). [3/2, +infinity). and (-infinity, 3/2} U{3/2, +infinity)

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


The domain of the inverse function is the range of the function.

What is the minimum value of the function (lower bound of the range)? That's the lower bound of the domain of the inverse function.

There is no upper bound on the range of the function, so there is no upper bound on the domain of the inverse function.