SOLUTION: Find the vertical and horizontal intercepts for -x^2 - 3x + 9.
(-x^2 means negative x squared)*
Find f(x) = ab^x if f(7) = 1 and if f(-1) = 2.
(ab^x means ab to the power
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-> SOLUTION: Find the vertical and horizontal intercepts for -x^2 - 3x + 9.
(-x^2 means negative x squared)*
Find f(x) = ab^x if f(7) = 1 and if f(-1) = 2.
(ab^x means ab to the power
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You can put this solution on YOUR website! Find the vertical and horizontal intercepts for -x^2 - 3x + 9.
(-x^2 means negative x squared)*
Solve:: -x^2-3x+9 = 0
Use the Quadratic Formula to get::
x = [3+-sqrt(9-4*-1*9)]/(2*-1)
x = [3+sqrt(45)]/-2 or x = [3-sqrt(45)]/-2
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Find f(x) = 0
y = 9
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Find f(x) = ab^x if f(7) = 1 and if f(-1) = 2.
(ab^x means ab to the power of x)*
ab^7 = 1
ab^-1 = 2
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Solve for "b"::
Divide top by bottom to get:
b^8 = 1/2
b = (1/2)^(1/8) = 0.917
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Solve for "a"::
ab^-1 = 2
a*1.091 = 2
a = 1.834
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Ans:: f(x) = 1.834*0.917^x
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Cheers,
Stan H.
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