SOLUTION: Write a polynomial f(x) in standard form that has the following characteristics. • Degree 3 • Leading coefficient of 6 • One double root at x = −6 • One root at x = 3/2

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: Write a polynomial f(x) in standard form that has the following characteristics. • Degree 3 • Leading coefficient of 6 • One double root at x = −6 • One root at x = 3/2       Log On


   



Question 1127747: Write a polynomial f(x) in standard form that has the following characteristics.
• Degree 3
• Leading coefficient of 6
• One double root at x = −6
• One root at x = 3/2
The following are my answers that I’ve gotten so far but are incorrect. F(x): 6x^3 +71x^2 + 204x -36.
F(x): x^2+ 228x -36. F(x): 6x^3+ 67.5 x^2 + 162x-162.

Found 2 solutions by htmentor, MathLover1:
Answer by htmentor(1343) About Me  (Show Source):
You can put this solution on YOUR website!
The function f(x) has the form a(x-b)^2(x-c)
where a is the leading coefficient, b is the double root and c is the single root
Thus f(x) = 6(x+6)^2(x-3/2)
Performing the multiplication, I get:
f(x) = 6x^3 + 63x^2 + 108x - 324

Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Degree 3
• Leading coefficient of +a=6
• One double root at x+%5B1%5D=+-6=x+%5B2%5D
• One root at x%5B3%5D+=+3%2F2
f%28x%29=a%28x-x+%5B1%5D%29%28x-x+%5B2%5D%29%28x-x+%5B3%5D%29
f%28x%29=a%28x-%28-6%29%29%28x-%28-6%29%29%28x-3%2F2%29
f%28x%29=6%28x-%28-6%29%29%5E2%28x-3%2F2%29
f%28x%29=6%28x%2B6%29%5E2%28x-3%2F2%29
f%28x%29=6%28x%5E2%2B12x%2B36%29%28x-3%2F2%29
f%28x%29=6%28x%5E3+%2B+%2821x%5E2%29%2F2+%2B+18x+-+54%29
f%28x%29=6x%5E3+%2B+6%2821x%5E2%29%2F2+%2B+6%2A18x+-+6%2A54
f%28x%29=6x%5E3+%2B63x%5E2+%2B+108x+-+324