Question 1127705: Find the number of different ways that the nine players on a baseball team can lineup Found 3 solutions by Alan3354, stanbon, ikleyn:Answer by Alan3354(69443) (Show Source):
You can put this solution on YOUR website! Find the number of different ways that the nine players on a baseball team can lineup
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Answer:: 9P9 = 9! = 9*8*7*...*2*1 = 362880 ways
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Cheers,
Stan H.
Any of 9 players can stand first. (9 options)
Any of remaining 8 players can stand second. (8 options)
Any of remaining 7 players can stand third (7 options)
. . . and so on . . .
In all, there are 9*8*7*6*5*4*3*2*1 ways = 9! ways = 362880 ways to form different lineup.
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It is the number of all possible permutations of 9 objects.
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