Question 1127683: Sandra has a total of one hundred fifty-one pennies, nickels and quarters. She has a total of $10.15. She has one more quarter than nickels and three times as many pennies as nickels. How many of each coin does she have?
amchaconz@allumni.stanford.edu
Found 3 solutions by addingup, greenestamps, ikleyn:
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! either you don't know your own email address or you mis-spelled it or it's a phony. I don't care, here's your answer:
p + n + q = 151
and:
n+1 = q
3n = p
0.01p + 0.05n + 0.25q = 10.15
now substitute for pennies and quarters:
0.01(3n) + 0.05n + 0.25(n+1) = 10.15
0.03n + 0.05n + 0.25n + 0.25 = 10.15
0.33n = 9.90
n = 30 Sandra has 30 nickels
Quarters = n+1 = 30 + 1 = 31
Pennies = 3n = 30(3) = 90
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Check:
30(0.05) + 31(0.25) + 90(0.01) = 10.15 Correct
:
Happy learning!
Answer by greenestamps(13200)  (Show Source):
Answer by ikleyn(52794)  (Show Source):
You can put this solution on YOUR website! .
Sandra has a total of one hundred fifty-one pennies, nickels and quarters. She has a total of $10.15.
She has one more quarter than nickels and three times as many pennies as nickels. How many of each coin does she have?
amchaconz@allumni.stanford.edu
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It is clear, from the first glance, that the problem is over-defined: it contains more data than it is required for the solution.
So, let be careful and will see what will happen in the course of the solution.
Let N be the number of nickels.
Then the number of quarters is (N+1) and the number of pennies is 3N.
Your "coin" equation is
N + (N+1) + 3N = 151.
5N + 1 = 151
5N = 151-1 = 150 ====> N = 150/5 = 30.
So far, we got 30 nickels, 31 quarter and 3*30 = 90 pennies.
CHECK. 30*5 + 31*25 + 90 = 10.15 cents. ! Correct !
The input data is consistent; the solution is correct.
Answer. 30 nickels, 31 quarter and 90 pennies.
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