SOLUTION: if a rocket is fired vertically into the air with a speed of 240 feet per second,it's height at time t seconds is given by h= -16t^2 + 240t. at the time will the rocket be 704 feet

Algebra ->  Customizable Word Problem Solvers  -> Misc -> SOLUTION: if a rocket is fired vertically into the air with a speed of 240 feet per second,it's height at time t seconds is given by h= -16t^2 + 240t. at the time will the rocket be 704 feet      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


    

Question 1127541: if a rocket is fired vertically into the air with a speed of 240 feet per second,it's height at time t seconds is given by h= -16t^2 + 240t. at the time will the rocket be 704 feet above the ground.
Found 2 solutions by Alan3354, FrankM:
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
if a rocket is fired vertically into the air with a speed of 240 feet per second,it's height at time t seconds is given by h= -16t^2 + 240t. at the time will the rocket be 704 feet above the ground.
----------
That's not a rocket, it's a projectile.
Rockets have thrust and accelerate upward.
------------
h(t) = -16t^2 + 240t = 704
-16t^2 + 240t - 704 = 0
Solve for t.
============
PS it's = it is

Answer by FrankM(1040) About Me  (Show Source):
You can put this solution on YOUR website!
704=-16t^2+240t
-16t^2+240t-704=0 (divide thru by -16)
t^2-15t+44=0
(t-11)(t-4)
Ans at t=4 and t=11