Question 1127516: Styline Menswear ordered short-sleeve shirts for $23 each and long-sleeve shirts for $28.50 each from Tommy Hilfiger. If the total order amounted to $9,862.50 for 375 shirts, how many short-sleeve were ordered?
Found 2 solutions by addingup, greenestamps:
Answer by addingup(3677)   (Show Source):
You can put this solution on YOUR website! Let short sleeve shirts be s and long sleeve l
:
s + l = 375 thus l= 375 - s
23s + 28.50l = 9,862.50 substitute for l:
23s + 28.50(375 - s) = 9,862.50
23s + 10,687.50 - 28.50s = 9,862.50
-5.50s = -825 divide both sides by -5.50, and remember that -/- = +
s = 150
150 short sleeves were ordered
Answer by greenestamps(13200)  (Show Source):
You can put this solution on YOUR website!
Using formal algebra....
(1) x+y = 375 [the total number of shirts is 375]
(2) 23x+28.50y = 9862.50 [the total price of the shirts is $9862.50]
Solve by any method you want. For me, the easiest is to multiply (1) by 23 and subtract from (2), giving an equation in y that I can solve.
I'll let you finish the algebraic solution.
Using logical reasoning, we can get the answer using basically the same calculations, but without the formal algebra.
(1) If all 375 shirts cost $23 each, the total sales would be $8625.
(2) The actual sales is $9862.05; the difference in the two totals is $9862.50-$8625 = $1237.50.
(3) The number of more expensive shirts is that difference of $1237.50, divided by the difference in price between the two shirts, $5.50.
(4) 1237.5/5.5 = 225
ANSWER: 225 long sleeve shirts and 375-225 = 150 short sleeve shirts were sold.
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