SOLUTION: Find θ, 0° ≤ θ < 360°, given the following information.
sin θ = − squr(2) / 2 and θ in QIV
θ = °
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-> SOLUTION: Find θ, 0° ≤ θ < 360°, given the following information.
sin θ = − squr(2) / 2 and θ in QIV
θ = °
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You can put this solution on YOUR website! Find θ, 0° ≤ θ < 360°, given the following information.
sin θ = − sqrt(2) / 2 and θ in QIV
arcsin(sqrt(2)/2) = 45 degrees is the reference angle
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θ = 360-45 = 315 degrees
Cheers,
Stan H.
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