SOLUTION: The sides of a triangle are 14cm, 48cm and 50cm. The perpendicular distance from the longest side to the midpoint of the shortest side is, in cm

Algebra ->  Trigonometry-basics -> SOLUTION: The sides of a triangle are 14cm, 48cm and 50cm. The perpendicular distance from the longest side to the midpoint of the shortest side is, in cm      Log On


   

Question 1127445: The sides of a triangle are 14cm, 48cm and 50cm. The perpendicular distance from the longest side to the midpoint of the shortest side is, in cm
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

use the area formula.
s+=+%281%2F2%29%2814%2B48%2B50%29+=+56
area of the triangle A=+sqrt%28s%28s-a%29%28s-b%29%28s-c%29%29+=+sqrt%2856%2A6%2A8%2A42%29+=336
Also, areaA=%281%2F2%2950%2Ah%2A2+=+50h,
h is the answer or the perpendicular distance from midpoint of "side 14" to "side 50"
The line segment connecting the midpoint to the vertex divides the triangle to two equal halves.
Thus,
50h=+336
h+=+168%2F25
h = 618%2F25