SOLUTION: Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air resistance.) A ball is thrown vertically upward from a height of 5 feet with an i

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Question 1127401: Assume the acceleration of the object is a(t) = −32 feet per second per second. (Neglect air resistance.) A ball is thrown vertically upward from a height of 5 feet with an initial velocity of 72 feet per second. How high will the ball go? Round your answer to two decimal places.
Answer by ikleyn(52788) About Me  (Show Source):
You can put this solution on YOUR website!
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Under given condition, the height of the ball over the ground level in feet is described by the quadratic function


    h(t) = -16t%5E2+%2B+72t+%2B+5.


Its maximum height will be achieved at  t = -b%2F%282a%29 = -72%2F%282%2A%28-16%29%29 = 2 seconds and

will be  h(2) = -16%2A2%5E2+%2B+72%2A2+%2B+5 = 85 ft.


The formula  t = -b%2F%282a%29  refers to the general form of a quadratic function


    f(x) = ax%5E2+%2B+bx+%2B+c


with the negative leading coefficient "a'.

See the lessons
    - Problem on a projectile moving vertically up and down
    - Problem on an arrow shot vertically upward
    - Problem on a ball thrown vertically up from the top of a tower
    - Problem on a toy rocket launched vertically up from a tall platform

Also,  you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this textbook under the topic "Projectiles launched/thrown and moving vertically up and dawn".


Save the link to this online textbook together with its description

Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson

to your archive and use it when it is needed.