SOLUTION: The sum of two numbers is 20. The difference between three times the first number and twice the second is 40. What are the two numbers

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Question 1127308: The sum of two numbers is 20. The difference between three times the first number and twice the second is 40. What are the two numbers
Found 3 solutions by josgarithmetic, ankor@dixie-net.com, stanbon:
Answer by josgarithmetic(39617)   (Show Source):
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Numbers, x and 20-x

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The numbers are 16 and 4.

Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website!
The sum of two numbers is 20.
a + b = 20
The difference between three times the first number and twice the second is 40.
3a - 2b = 40
What are the two numbers?
Multiply the 1st equation by 2, add to the 2nd equation
2a + 2b = 40
3a - 2b = 40
----------------addition eliminates b, find a
5a + 0 = 80
a = 80/5
a = 16
find b
16 + b = 20
b = 20 - 16
b = 4
:
;
Check in the 2nd equation
3(16) - 2(4) =
48 - 8 = 40

Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website!
The sum of two numbers is 20. The difference between three times the first number and twice the second is 40. What are the two numbers ?
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Equations::
x + y = 20
3x-2y = 40
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Solving by substitution::
x = 20-y
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So, 3(20-y)-2y = 40
60-5y = 40
5y = 20
y = 4
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Then x = 20-y = 16
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Cheers,
Stan H.
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