SOLUTION: Find the area of a triangle bounded by the y-axis, the line f(x) = 6 − 6/7x, and the line perpendicular to f(x) that passes through the origin. (Round your answer to two deci

Algebra ->  Linear-equations -> SOLUTION: Find the area of a triangle bounded by the y-axis, the line f(x) = 6 − 6/7x, and the line perpendicular to f(x) that passes through the origin. (Round your answer to two deci      Log On


   

Question 1127239: Find the area of a triangle bounded by the y-axis, the line f(x) = 6 − 6/7x, and the line perpendicular to f(x) that passes through the origin. (Round your answer to two decimal places.)
*This is what I have came up with so far:
f(x)= y = 6-6/7x.
Slope =-6/7.
-1/-6/7= 7/6.
7/7x=6-6/7x
From here I am lost on what to do next. Multiplying each fraction by its reciprocal seems to be the next step, but I'm not entirely sure if it is the correct step.*
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
Find the area of a triangle bounded by:
the y-axis,
the line f%28x%29+=+6+-%286%2F7%29x=> a slope=+%28-6%2F7%29
the line perpendicular to f(x) that passes through the origin
first find perpendicular line y=mx
m=-1%2F%28-6%2F7%29=7%2F6
y=%287%2F6%29x



find intersection point both lines:
%287%2F6%29x%29+=+6+-%286%2F7%29x
%287%2F6%29x%2B%286%2F7%29x+=+6+
%287%2F6%2B6%2F7%29x+=+6+
%2885%2F42%29x+=+6+
x+=+6%2F%2885%2F42%29+
x+=+2.96+
find y
y=%287%2F6%292.96
y=3.45
intersection point C is at (2.96,3.45)

graph all:


the length of the base: AB=6
the length of the altitude to the base: 2.96
the area of the triangle ABC is:
A=%281%2F2%29%2A6%2A2.96
A=3%2A2.96
A=8.88 square units