SOLUTION: suppose Tom has 13 coins totaling $1.60 if he only has dimes and quarters how many of each type does he have

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Question 1127210: suppose Tom has 13 coins totaling $1.60 if he only has dimes and quarters how many of each type does he have
Found 2 solutions by josgarithmetic, addingup:
Answer by josgarithmetic(39628) About Me  (Show Source):
You can put this solution on YOUR website!
x quarters
13-x dimes
25x%2B10%2813-x%29=160
5x%2B2%2813-x%29=32
5x%2B26-2x=32
3x=32-26
3x=6
x=2

2 quarters and 11 dimes

Answer by addingup(3677) About Me  (Show Source):
You can put this solution on YOUR website!
d + q = 13 therefore q = 13 - d
0.10d + 0.25q = 1.60
0.10d + 0.25(13 - d) = 1.60
0.10d + 3.25 - 0.25d = 1.60
-0.15d = -1.65 divide both sides by 0.15 and remember -/- = +
d = 11 this is how many dimes he has
13 - 11 = 2 this is how many quarters he has
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Check:
0.10(11) + 0.25(2) = 1.60
1.10 + 0.50 = 1.60 Correct