SOLUTION: factor each polynomial (x+y)squared + 6(x+y) + 9

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Question 112703: factor each polynomial
(x+y)squared + 6(x+y) + 9

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Let w=x+y

So now let's factor w%5E2+%2B+6w+%2B+9


Solved by pluggable solver: Factoring using the AC method (Factor by Grouping)


Looking at the expression w%5E2%2B6w%2B9, we can see that the first coefficient is 1, the second coefficient is 6, and the last term is 9.



Now multiply the first coefficient 1 by the last term 9 to get %281%29%289%29=9.



Now the question is: what two whole numbers multiply to 9 (the previous product) and add to the second coefficient 6?



To find these two numbers, we need to list all of the factors of 9 (the previous product).



Factors of 9:

1,3,9

-1,-3,-9



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to 9.

1*9 = 9
3*3 = 9
(-1)*(-9) = 9
(-3)*(-3) = 9


Now let's add up each pair of factors to see if one pair adds to the middle coefficient 6:



First NumberSecond NumberSum
191+9=10
333+3=6
-1-9-1+(-9)=-10
-3-3-3+(-3)=-6




From the table, we can see that the two numbers 3 and 3 add to 6 (the middle coefficient).



So the two numbers 3 and 3 both multiply to 9 and add to 6



Now replace the middle term 6w with 3w%2B3w. Remember, 3 and 3 add to 6. So this shows us that 3w%2B3w=6w.



w%5E2%2Bhighlight%283w%2B3w%29%2B9 Replace the second term 6w with 3w%2B3w.



%28w%5E2%2B3w%29%2B%283w%2B9%29 Group the terms into two pairs.



w%28w%2B3%29%2B%283w%2B9%29 Factor out the GCF w from the first group.



w%28w%2B3%29%2B3%28w%2B3%29 Factor out 3 from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



%28w%2B3%29%28w%2B3%29 Combine like terms. Or factor out the common term w%2B3



%28w%2B3%29%5E2 Condense the terms.



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Answer:



So w%5E2%2B6%2Aw%2B9 factors to %28w%2B3%29%5E2.



In other words, w%5E2%2B6%2Aw%2B9=%28w%2B3%29%5E2.



Note: you can check the answer by expanding %28w%2B3%29%5E2 to get w%5E2%2B6%2Aw%2B9 or by graphing the original expression and the answer (the two graphs should be identical).





Now replace w with x+y

%28x%2By%2B3%29%28x%2By%2B3%29


So %28x%2By%29%5E2+%2B+6%28x%2By%29+%2B+9 factors to %28x%2By%2B3%29%28x%2By%2B3%29