SOLUTION: There consecutive odd numbers are such that the square of the first is 72 less than the square of the third. Find the three numbers.

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Question 1126936: There consecutive odd numbers are such that the square of the first is 72 less than the square of the third. Find the three numbers.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
Let the consecutive odd numbers be
n, n+2, and n+4
-----------------------
+n%5E2+=+%28+n+%2B+4+%29%5E2+-+72+
+n%5E2+=+n%5E2+%2B+8n+%2B+16+-+72+
+0+=+8n+-+56+
+8n+=+56+
+n+=+7+
+n+%2B+2+=+9+
+n+%2B+4+=+11+
7, 9, and 11
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check:
+7%5E2+=+11%5E2+-+72+
+49+=+121+-+72+
+49+=+49+
OK