SOLUTION: I am a learning coach trying to help a student. Please help me try to explain how to do the calculation (do not know the calculation) A fruit bowl contains 4 apples, 6 bananas,

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Question 1126900: I am a learning coach trying to help a student.
Please help me try to explain how to do the calculation (do not know the calculation)
A fruit bowl contains 4 apples, 6 bananas, 5 pears and 1 orange.
Suppose 2 pieces of fruits are selected from the bowl, and the first piece of fruit selected is replaced before the second piece of fruit is selected. What is the probability 2 pears are selected? What calculation would you use?
Found 2 solutions by Theo, ikleyn:
Answer by Theo(13342)   (Show Source):
You can put this solution on YOUR website!
4 apples, 6 bananas, 5 pears, 1 orange.
total is 16 pieces of fruit.

probability of first piece to be a pear is 5/16.
since the fruit is replaced before picking again, the probability of the second piece being a pear is also 5/16.

the probability of both pieces being selected is 5/16 * 5/16 = 25/256.

here's a reference.

https://www.mathsisfun.com/data/probability-events-conditional.html

Answer by ikleyn(52788)   (Show Source):
You can put this solution on YOUR website!
.
You can find many solved elementary probability problems in the lessons

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    - OVERVIEW of lessons on Probability (*)

in this site.   You can learn the elementary probability by simply reading these lessons.

The good position to observe all these lessons ("top view") is the last lesson (*) of the list.