SOLUTION: one number is seven more than twice another. if their sum is decrease by ten the result is twelve find the numbers

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Question 1126805: one number is seven more than twice another. if their sum is decrease by ten the result is twelve find the numbers
Answer by MathLover1(20850) About Me  (Show Source):
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let one number be x, and other number be y
if x is seven+more than twice y, we have
x=2y%2B7.......eq.1

if their sum is decrease by ten the result is twelve; so, we have
x%2By-10=12....eq.2
substitute x from eq.1
2y%2B7%2By-10=12....eq.2 ...solve or y
3y-3=12
3y=12%2B3
3y=15
y=15%2F3
y=5
now find x
x=2y%2B7.......eq.1
x=2%2A5%2B7
x=10%2B7
x=17

so, one number is 17, and the other number is 5