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2x + y = 13, (1)
4x + 5y = 11. (2)
Multiply eq(1) by the factor 2 (both sides). Keep the equation (2) as is. You will get an equivalent system
4x + 2y = 26 (1')
4x + 5y = 11 (2')
Now subtract eq(1') from eq(2'). The terms "4x" will cancel each other, (<<<---=== it is how the Elimination method works)
and you will get a single equation for the unknown "y"
5y - 2y = 11 - 26, or
3y = -15,
which implies y = -15/3 = -5.
Now from equation (1), 2*x - 5 = 13; hence, 2x = 13 + 5 = 18 and x = 18/2 = 9.
Check the solution on your own by substituting the found values into the original equation.
Do it on your own (I just did it mentally).
Answer x= 9; y= -5.
Solved.
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See the lesson
- Solution of the linear system of two equations in two unknowns by the Elimination method
in this site.