SOLUTION: "Write an equation (y=mx+b) of the line that passes through the given point and is parallel to the given line." x y (8, -3) 4y - 3x = 20 I need this solved

Algebra ->  Graphs -> SOLUTION: "Write an equation (y=mx+b) of the line that passes through the given point and is parallel to the given line." x y (8, -3) 4y - 3x = 20 I need this solved       Log On


   

Question 1126593: "Write an equation (y=mx+b) of the line that passes through the given point and is parallel to the given line."
x y
(8, -3)
4y - 3x = 20
I need this solved fast it's due tommorow, please!
Answer by MathLover1(20849) About Me  (Show Source):
You can put this solution on YOUR website!
y=mx%2Bb
an equation of the line that passes through the point
(x,+++y)=(8,+-3)

and is parallel to the given line 4y+-+3x+=+20
first recall that parallel lines have same slope
so, write 4y+-+3x+=+20 in slope-intercept form y=mx%2Bb
4y++=3x%2B+20
y++=3x%2F4%2B+20%2F4
y++=%283%2F4%29x%2B+5 => as you can see a slope m=3%2F4

so far, the equation of the parallel line is
y=%283%2F4%29x%2Bb ...now use given point (x,+++y)=(8,+-3) to find b
-3=%283%2F4%298%2Bb
-3=%283%2Fcross%284%29%29cross%288%292%2Bb
-3=3%2A2%2Bb
-3=6%2Bb
b=-3-6
b=-9
and, your equation is:
y=%283%2F4%29x-9