Question 1126567: A person owns two shops. This year the telephone bill for the first shop was $530 less than three times the telephone bill for the second shop. The total telephone expense for both shops was $2758. What was the cost of each shop's telephone service for the year?
Answer by sbro7568(4)   (Show Source):
You can put this solution on YOUR website! To represent the bill for the first shop, we will use the variable x. To represent the bill for the second shop, we will use the variable y.
Since the first shop's bill is $530 less than 3 times the second shop's bill, we can put together an equation for the first shop's bill based on the second shop's:  .
Now, since the total for both shops was $2758, we can create an equation for the total:  .
We can then plug in the first equation we created, , to replace x, and end up with  . When we simplify this equation, we get  . Then, we can add 530 to both sides to get  . Since y represents the second shop's bill, the bill must be $822 for that shop.
To get the first shop's bill, we can plug in 822 to the first equation we made, to get  . When we simplify this equation, we get  . Therefore, the first shop's bill is $1936.
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tl;dr:
First shop's bill = $1936
Second shop's bill = $822
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