SOLUTION: Hello, I need to find restrictions and simplify this problem: But I have no idea how to do so. 6x^2+13x-63 __Fraction__ 3x^2+11x-42

Algebra ->  Rational-functions -> SOLUTION: Hello, I need to find restrictions and simplify this problem: But I have no idea how to do so. 6x^2+13x-63 __Fraction__ 3x^2+11x-42      Log On


   



Question 1126563: Hello,
I need to find restrictions and simplify this problem:
But I have no idea how to do so.
6x^2+13x-63
__Fraction__
3x^2+11x-42

Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

%286x%5E2%2B13x-63%29%2F%28+3x%5E2%2B11x-42+%29=%282+x+%2B+9%29%2F%28x+%2B+6%29+
true for x%3C%3E-6 and x%3C%3E7%2F3-> restrictions

Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


You simplify fractions by canceling like factors in the numerator and denominator.

Since you can only cancel common factors, you can't simplify the fraction in its given form. You need to factor the numerator and denominator and look for a factor common to both.

There are dozens of methods for factoring a trinomial into the product of two binomials. But instead of blindly trying to factor either the numerator or denominator alone, let's use the knowledge that the fraction PROBABLY can be simplified, which means there should be a binomial factor common to both numerator and denominator.

With leading terms 6x^2 and 3x^2, and constant terms 42 and 63, a good bet for a common binomial factor is either 3x+7 or 3x-7.

Trying those with the given numerator and denominator, you should find



So the simplified fraction is %282x%2B9%29%2F%28x%2B6%29

The restrictions are all the values that make the denominator of the ORIGINAL, UNSIMPLIFIED fraction equal to 0: 7/3 and -6.