SOLUTION: Koech left home to a shopping centre 12km away, running at 8km/hr. 15minutes later, mutua left the same home and cycled to the shopping centre at 20km/hr. Calculate the distance to

Algebra ->  Finance -> SOLUTION: Koech left home to a shopping centre 12km away, running at 8km/hr. 15minutes later, mutua left the same home and cycled to the shopping centre at 20km/hr. Calculate the distance to      Log On


   

Question 1126541: Koech left home to a shopping centre 12km away, running at 8km/hr. 15minutes later, mutua left the same home and cycled to the shopping centre at 20km/hr. Calculate the distance to the shopping centre at which mutua caught up with koech?
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!

Koech left home to a shopping center 12km away, running at 8%28km%2Fh%29.
d=12km
s=8%28km%2Fh%29
12km=8%28km%2Fh%29%2At..........eq.1
fifteen minutes later, mutual left the same home and cycled to the shopping center at 20%28km%2Fh%29
15min=%281%2F4%29h=0.25h+
s=20%28+km%2Fh%29
time is t-0.25h
d is same: d=12km
12km=20%28+km%2Fh%29%28t-0.25h%29....eq.2
they will meet when
8%28km%2Fh%29%2At=20%28+km%2Fh%29%28t-0.25h%29 solve for t
8cross%28%28km%2Fh%29%29%2At=20cross%28%28+km%2Fh%29%29%28t-0.25h%29
8t=20%28t-0.25h%29
8t=20t-20%2A0.25h
8t=20t-5h
20t-8t=5h
12t=5h
t=%285%2F12%29h
t≈0.416667h
ind distance:
d=8%28km%2Fh%29%2At
d=8%28km%2Fh%29%2A0.416667h
d=3.333333km-> Koech
d=20%28+km%2Fh%29%280.416667h-0.25h%29
d=20%28+km%2Fh%29%280.166666667h%29
d=3.3333333km->the distance to the shopping center at which Mutua caught up with Koech